27=(1/6)^x

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Solution for 27=(1/6)^x equation:



27=(1/6)^x
We move all terms to the left:
27-((1/6)^x)=0
Domain of the equation: 6)^x)!=0
x!=0/1
x!=0
x∈R
We add all the numbers together, and all the variables
-((+1/6)^x)+27=0
We multiply all the terms by the denominator
-((+1+27*6)^x)=0
We calculate terms in parentheses: -((+1+27*6)^x), so:
(+1+27*6)^x
We add all the numbers together, and all the variables
163^x
Back to the equation:
-(163^x)
x=0/1
x=0
Równanie nie ma rozwiązania

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